Answer:
[tex]b)151 {in.}^{3} [/tex]
Step-by-step explanation:
[tex]v = \frac{1}{3} \pi {r}^{2} h[/tex]
[tex] = \frac{1}{3} \times \frac{22}{7} \times {4}^{2} \times 9[/tex]
[tex] = \frac{1}{3} \times \frac{22}{7} \times 16 \times 9[/tex]
[tex] = \frac{3168}{21} [/tex]
[tex] = 150.857[/tex]
[tex]approximately \: 151 {in.}^{3} [/tex]
