Respuesta :
Answer:option 3, Y is greater than or = to -1
Step-by-step explanation:
I took it on Edge
The range of [tex]y=\sqrt{x-5} -1[/tex] is [tex][-1,\infty)[/tex].
Given,
[tex]y=\sqrt{x-5} -1[/tex].
We have to find the range of the expression.
Set the radicand in [tex]\sqrt{x-5}[/tex] greater than or equal to 0 to find where the expression is defined.
[tex]\sqrt{x-5} \geq 0[/tex]
[tex]x-5\geq 0[/tex]
Add 5 to both sides of the inequality, we get
[tex]x\geq 5[/tex]
The domain is all values of [tex]x[/tex] that make the expression defined.
Interval Notation:
[tex][5,\infty )[/tex]
Set-Builder Notation:
[tex][x|x\geq 5][/tex]
The range of an even indexed radical starts at its starting point ( 5 , − 1 ) and extends to infinity.
Interval notation:
[tex][-1,\infty)[/tex]
Hence the range of above function is [tex][-1,\infty)[/tex].
For more details on range follow the link:
https://brainly.com/question/8041076