Morgan set up a Web site and kept track of how many people clicked on it. By the end of the second day, the Web site had received 4 clicks and by the end of the fourth day, it had received 16 clicks.

She wrote two functions f(d) to model the number of clicks, where d is the number of days since she set up the Web site. One of the functions is exponential, and the other is linear.

Drag equations and statements to the table to show the functions she wrote and to show which function has the greater initial value and the lesser initial value

Respuesta :

Answer:

Exponential function:

[tex]f(d) =2^d[/tex]

Linear function:

[tex]f(d) = 2\times f(d-1)[/tex]

Step-by-step explanation:

Given that:

Number of clicks by the end of 2nd day = 4

Number of clicks by the end of 4th day = 16

To find:

The function f(d) to model number of clicks in exponential and linear form.

Solution:

Given that with a value d = 2, f(d) = 4 and

d = 4, f(d) = 16

4 is [tex]2^{2}[/tex]

and 16 is [tex]2^{4}[/tex]

We can see that 2 has a power 'Number of days'.

So, exponential function can be written as:

[tex]f(d) = 2^d[/tex]

As per the pattern given, at the end of 2nd day, there are 4 clicks

by the end of 3rd day there will be 8 clicks and

by the end 4th day it has 16 clicks.

It means that by the end of present day the number of clicks have doubled than that of clicks by end of previous day.

So, we can write the function

[tex]f(d) = 2\times f(d-1)[/tex]

So, the answer is:

Exponential function:

[tex]f(d) =2^d[/tex]

Linear function:

[tex]f(d) = 2\times f(d-1)[/tex]