Answer:
[tex]\boxed{\sf \ \ \ (x-4)(x-7) \ \ \ }[/tex]
Step-by-step explanation:
Hello,
from the expression we can say that the sum of the two zeroes is 11 and the product is 28
4 + 7 = 11
4 * 7 = 28
so we can write
[tex]x^2-11x+28=(x-4)(x-7)[/tex]
hope this helps