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A long straight metal rod has a radius of 2.0 mm and a surface charge of density 0.40 nC/m2. Determine the magnitude of the electric field 3.0 mm from the axis.

Respuesta :

Answer:

Explanation:

Gauss Theorem

E2πrL=o2πRL/εo

then

E=oR/(rεo)

E=(0.4*10^-9*2*10^-3) / (3*10^-3*8.85*10^-12)

= 30.13 N/C

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