Respuesta :
Answer:
The answer is "(0.461 , 7.206)"
Step-by-step explanation:
In the given question some information is missing, that is data. so, the correct answer to this question can be defined as follows:
UnLogged:
[tex]x_1=17.500\\s_1=3.529\\n_1=12[/tex]
Logged:
[tex]x_2=13.667\\ s_2=4.500\\n_2=9\\[/tex]
formula of std error:
[tex]\ std \ error =\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}[/tex]
[tex]=\sqrt{\frac{3.529^2}{12}+\frac{4.500^2}{9}}\\\\=\sqrt{\frac{3.529^2\times 3+4.500^2\times 4}{36}}\\\\=1.8133[/tex]
Point differential estimation =[tex]x_1-x _2[/tex]
[tex]= 17.500-13.667\\=3.833[/tex]
For 90 percent t= 1.860 Cl & 8 df
error of margin E = [tex]t\times \ std \ error[/tex]
[tex]= 1.860 \times 1.8133\\= 3.373[/tex]
Lower bound =mean difference -E=0.461
Upper bound = mean difference+ E=7.206
In the above 90% confidence interval were the population mean= (0.461 , 7.206)
