Answer: Therefore, the volume of 0.001 M KI is 61 ml.
Explanation:
The balanced chemical reaction is :
[tex]2KI+Cu(NO_3)_2\rightarrrow CuI_2+2KNO_3[/tex]
According to the neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]KI[/tex] solution = 0.100 M
[tex]V_1[/tex] = volume of [tex]KI[/tex] solution = ?
[tex]M_2[/tex] = molarity of [tex]Cu(NO_3)_2[/tex] solution = 0.200 M
[tex]V_2[/tex] volume of [tex]Cu(NO_3)_2[/tex] solution = 15.25 ml
[tex]n_1[/tex] = valency of [tex]KI[/tex] = 1
[tex]n_2[/tex] = valency of [tex]Cu(NO_3)_2[/tex] = 2
Putting in the values we get:
[tex]1\times 0.100\times V_1=2\times 0.200\times 15.25[/tex]
[tex]V_1=61ml[/tex]
Therefore, the volume of 0.001 M KI is 61 ml.
