Answer:
Explanation:
Frictional force acting on incline = μ mg cosθ
μ is coefficient of friction , m is mass of object , θ is incline
= .09 x m x 9.8 x cos 28
= .78 m
work done by friction
= frictional force x displacement
= - .78m x 100
= - 78m
Potential energy of sli at height
= mgh
= m x 9.8 x 100 sin 28
= 460.08 m
net energy at the base
= 460.08m - 78 m
= 382.08 m
This will be in the form of kinetic energy .
1/2 m v² = 382.08 m
.5 x v² = 382.08
v = 27.64 m/s
After that it travels on plane surface .
Let the distance travelled be d
work done by frictional force
= μ mg x d
= .09 x m x 9.8 x d
This will be equal to kinetic energy at the base
.09 x m x 9.8 x d = 382.08 m
d = 433.2 meter .
