Answer:
Explanation:
Let the common acceleration be a .
Considering motion of mL
20.5g - TL = 20.5 a
Considering motion of mR
TR - 11.7g = 11.7 a
TR-TL + 20.5 g- 11.7 g = (20.5 + 11.7 ) a
TL-TR = 8.8 g - 32.2 a
Considering motion of wheel
( TL - TR ) x rp = 1/2 x mp x rp² x α where α is angular acceleration of wheel
= ( TL - TR ) = 1/2 x mp x a ( a = α x rp )
Putting the values from equation above
8.8g - 32.2a = .5 mp a
8.8g = 32.2 a + .5 x 5.33 a
8.8 g = 34.865 a
a = 2.47 m /s²
20.5 g - TL = 20.5 a
TL = 20.5 x 9.8 - 20.5 x 2.47
= 150.26 N
TR - 11.7g = 11.7 a
TR - 11.7 x 9.8 = 11.7 x 2.47
TR = 143.56 N