Answer:
The Pressure inside the container 5.56 atm
Explanation:
Given that:
the mass of CO2 = 50.0g
molar mass of CO2= 44 g/mol
So; the number of moles of CO2 = mass/molar mass
= 50.0 g/44 g/mol
= 1.1364 mol
Volume of the container = 5.0 L
Temperature = 25°C = ( 25+273.15)K = 298.15 K
universal gas constant R = 0.08206 L atm mol⁻¹ K⁻¹
Using Ideal Gas Equation PV = nRT
P = nRT/V
P = (1.1364 × 0.08206 × 298.15) / 5.0
P = 27.80337718/ 5.0
P = 5.560675436 atm
P ≅ 5.56 atm