Answer:
The answer is:
[tex]H_0:\mu=2.2\\H_1:\mu> 2.2[/tex]
Explanation:
[tex]H_0:\mu=2.2\\H_1:\mu> 2.2[/tex]
The test value of statistic t= [tex]\frac{\bar x-\mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]=\frac{2.31688-2.2}{0.206915}\\\\=0.56[/tex]
The value of P = P(T>0.56)
=1-P(T<0.56)
=1-0.712
=0.288