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A sample of gas in a cylinder as in the example in Part A has an initial volume of 48.0 L , and you have determined that it contains 1.80 moles of gas. The next day you notice that some of the gas has leaked out. The pressure and temperature remain the same, but the volume has changed to 12.0 L . How many moles of gas (n2) remain in the cylinder

Respuesta :

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

[tex]\frac{n1}{V1} = \frac{n2}{V2}[/tex]

we can say that

[tex]n2 = n1 \times \frac{V2}{V1}[/tex]

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

[tex]= 1.80 \times \frac{12.0\ L}{48.0\ L}[/tex]

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

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