An electron (mass=9.11 X 10^-31kg) leaves a TV picture tube with zero initial speed and reaches the screen 1.90cm away at 3.00 X 10^6 m/s. Ignore gravity and find the net force. (1): 2.28 X 10^-19N (2): 2.28 X 10^-16N (3): None of the above

Respuesta :

Answer:

2.16 × 10^-16N

Explanation:

The computation of the net force is shown below:

Data provided in the question

Electron mass = 9.11 × 10^-31kg

V_o = 0

V_f =  3.00 × 10^6 m/s

s = 1.90 cm i.e 1.9 × 10^-2

Based on the above information, the force is

As we know that

[tex]Force\ f = ma = \frac{mv^2}{2s}\\\\ = \frac{(9.11\times 10^{-31})(3\times 10^{6})^2}{2(1.9\times 10^{-2})}[/tex]

= 2.16 × 10^-16N

Hence, the last option is correct

Basically we applied the above formula to determine the net force