Answer:
48 m/s
Explanation:
Given:
Δx = 300 m − 25 m = 275 m
v₀ = 16.5 m/s
a = 3.7 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (16.5 m/s)² + 2 (3.7 m/s²) (275 m)
v = 48 m/s
48.03 m/s
acceleraion, a = 3.7 m/s^2
distance traversed, S = 300-25 = 275 m
initial velocity, v0 = 16.5 m/s
Using kinematics formula
v1^2 - v0^2 = 2aS
Final velocity,
v1 = sqrt(2aS + v0^2)
= sqrt(2*3.7*275 + 16.5^2)
= 48.03 m/s
