Respuesta :
Answer:
Explained below.
Step-by-step explanation:
The information provided is:
n = 200
X = 106
α = 0.05
The sample proportion is:
[tex]\hat p=\frac{X}{n}=\frac{106}{200}=0.53[/tex]
(a)
A hypothesis test is to performed to determine whether more than half of all drivers drive a car made in this country.
The hypothesis is:
H₀: The proportion of drivers driving a car made in this country is less than or equal to 50%, i.e. [tex]\mu_{p}\leq 0.50[/tex]
Hₐ: The proportion of drivers driving a car made in this country is more than 50%, i.e. [tex]\mu_{p}> 0.50[/tex]
(b)
Compute the value of the test statistic:
[tex]Z=\frac{\hat p-\mu_{p}}{\sqrt{\frac{\mu_{p}(1-\mu_{p})}{n}}}[/tex]
[tex]=\frac{0.53-050}{\sqrt{\frac{0.50(1-0.50)}{200}}}\\\\=0.8485\\\\\approx 0.85[/tex]
Compute the p-value as follows:
[tex]p-value=P(Z_{0.05}>0.85)\\=1-P(Z_{0.05}<0.85)\\=1-0.80234\\=0.19766\\\approx 0.198[/tex]
*Use a z-table.
Thus, the p-value of the test is 0.198.
(c)
Decision rule:
Reject the null hypothesis if the p-value is less than the significance level.
p-value = 0.198 > α = 0.05
The null hypothesis will not be rejected.
The correct option is (A).
(d)
Conclusion:
There is not enough evidence at 0.05 level of significance to support the claim that the proportion of drivers driving a car made in this country is more than 50%.
