Answer:
a)Claims: P>0.5("MOST" of the adult erase their personal information)
b)Statistics test= 4.746
Step-by-step explanation:
we were given {p}=60% =0.60
where n= 563
since most of adults erase all their personal information online, then (p> 0.5
p=0.5
q=1-p=1-0.5=0.5
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
The value of the statistic test is 4.746 and this can be determined by using the given data.
Given :
A software firm survey of 563 randomly selected adults showed that 60% of them would erase all of their personal information online if they could.
It is given that [tex]\rm \bar{P}[/tex] = 60% = 0.60 and n = 563.
Claim: Most adults would erase all of their personal information online if they could that means (P > 0.5). Therefore:
q = 1 - P = 1 - 0.5 = 0.5
Now, to determine the value of the statistic test, the following formula can be used:
[tex]\rm \dfrac{\bar{P}-P}{\sqrt{\dfrac{Pq}{n}} } = \dfrac{0.6-0.5}{\sqrt{\dfrac{0.5\times0.5}{563}} }=4.746[/tex]
Therefore, the value of the statistic test is 4.746.
For more information, refer to the link given below:
https://brainly.com/question/23091366
