Answer:
You will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.
Explanation:
The distance can be calculated using the following equation:
[tex] \frac{I_{1}}{I_{2}} = \frac{D_{2}^{2}}{D_{1}^{2}} [/tex]
Where:
I₁ = 158 mRem/h
I₂ = 17 mRem/h
D₁ = 4 ft.
D₂=?
Hence, the distance D₂ is:
[tex] D_{2} =\sqrt{\frac{I_{1}}{I_{2}}*D_{1}^{2}} = \sqrt{\frac{158 mRem/h}{17 mRem/h}*(4 ft)^{2}} = 12.2 ft [/tex]
Therefore, you will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.
I hope it helps you!
