Answer:
The answer is given below
Step-by-step explanation:
The equation of a quadratic function is given by:
Ax² + Bx + C where A, B and C are the coefficients of the quadratic equation. If the coefficient of x² (i.e A) is a negative value then the graph opens down, the value of C determines the y intercept.
The equation of a parabola with y-intercept greater than 3 and opens down can be given as -2x² -6x + 4. Since the coefficient of x² is negative it opens down and C = 4, it has a y intercept of 4 > 3
Let us assume a vertical stretch of 2, the new equation becomes:
2(-2x² -6x + 4)
-4x² - 12x + 8
To solve:
-4x² - 12x + 8 = 0
A = -4, B = -12 and C = 8
Using the quadratic formula:
[tex]x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}\\ x=\frac{-(-12) \pm \sqrt{(-12)^2-4(-4)(8)} }{2(-4)}=\frac{12 \pm 16.49}{-8} \\x= -3.6 \ or \ x=0.6[/tex]
