Answer:
The value of the effective (rms) voltage of the applied source in the circuit is 132 V
Explanation:
Given;
effective (rms) voltage of the resistor, [tex]V_R[/tex] = 65 V
effective (rms) voltage of the inductor, [tex]V_L[/tex] = 140 V
effective (rms) voltage of the capacitor, [tex]V_C[/tex] = 80 V
Determine the value of the effective (rms) voltage of the applied source in the circuit;
[tex]V= \sqrt{V_R^2 + (V_L^2-V_C^2} )\\\\V= \sqrt{65^2 + (140^2-80^2} )\\\\V = \sqrt{4225+ 13200} \\\\V = \sqrt{17425} \\\\V = 132 \ V[/tex]
Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.
