muneeramohamed65
contestada

3. In the diagram O is the centre of
the circle.
AOC is a straight line.
Angle BAO is 24° and Angle ADO is 42°​
a)find angle CAD
b)find the size of ACB
c)find the size of angle BCD

3 In the diagram O is the centre ofthe circleAOC is a straight lineAngle BAO is 24 and Angle ADO is 42afind angle CADbfind the size of ACBcfind the size of angl class=

Respuesta :

Answer:

Step-by-step explanation:

a) angle CAD= angle ODA ( in triangle OAD, OA=OD(same radius) angels opp                          to equal sides are equal)

hence angle CAD=42

b)angle b =90(angle subtended by diameter)

hence using angle sum property in triABC,

angle ACB=66-------------eq4

c) in tri OAD,

Angle AOD=180-(42+42)-------(using angle sum prop.)

=> 96-----------------eq1

angleACD=1/2 Angle AOD ( angle subtende by an arc at centre is double the angle subtended...)

hence angle ACD =1/2 x 96(from eq1)

angleACD=48--------------eq3

from eq 3,and eq4,

angle BCD= 48+66

=114 degree...

hope this helped you........pls mark brainliest

Otras preguntas