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At the movie theatre, child admission is $5.10 and adult admission is $9.00 .
On Wensday, twice as many adults tickets as child tickets were for a total of $831.60.

How many child tickets were sold that day?

Respuesta :

Answer:

[tex] 5.10 X +9.00 Y = 831.60[/tex]

We also know that for Wedneday we have two times tickets for adults compared to child so we have

[tex] Y =2x[/tex]

And using this condition we have:

[tex] 5.10 X + 18 X = 831.60[/tex]

And solving for X we got:

[tex] X= \frac{831.60}{23.1}=36[/tex]

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue  for Wednesday was 831.60. So then we can set up the following equation for the total revenue

[tex] 5.10 X +9.00 Y = 831.60[/tex]

We also know that for Wedneday we have two times tickets for adults compared to child so we have

[tex] Y =2x[/tex]

And using this condition we have:

[tex] 5.10 X + 18 X = 831.60[/tex]

And solving for X we got:

[tex] X= \frac{831.60}{23.1}=36[/tex]

So then the number of tickets sold for child are 36

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