Answer:
a) m = 26.03 kg
b) V = 26000 cm³
Explanation:
a) The mass of water that should evaporate from the skin can be calculated using the following equation:
[tex] m*Q = M*C*\Delta T [/tex]
Where:
m: is the mass of water =?
Q: is the heat of vaporization of water = 2.42x10⁶ J/kg
C: is the specific heat capacity = 3480 J/(kg*K)
ΔT: is the temperature difference = 1.30 °C = 274.3 K
M: is the mass of the man = 66.0 kg
[tex] m= \frac{M*C*\Delta T}{H} = \frac{66.0 kg*3480 J/(kg*K)*274.3 K}{2.42\cdot 10^{6} J/kg} = 26.03 kg [/tex]
Hence, 26.03 kg of the mass of water must evaporate from the skin.
b) The volume (V) of water is:
[tex] V = \frac{m}{d} [/tex]
Where:
d: is the density of water = 997 kg/m³
[tex] V = \frac{26.03 kg}{997 kg/m^{3}} = 0.026 m^{3} = 26000 cm^{3} [/tex]
Compared to a soft drink can of 355 cm³, the man should drink approximately 73 cans of soft drink to compensate for the evaporated water.
I hope it helps you!
