Complete Question
The complete question is shown on the first uploaded image
Answer:
The current is [tex]I = 4.2 \ A[/tex]
Explanation:
From the question we are told that
The voltage of battery is [tex]V = 25 V[/tex]
The capacitance of capacitor is [tex]C = 15 \mu F[/tex]
The resistance of the resistor is [tex]R = 6 \Omega[/tex]
Generally the current at the instant the capacitor starts charging is
[tex]I = \frac{V}{R}[/tex]
substituting values
[tex]I = \frac{25}{6}[/tex]
[tex]I = 4.2 \ A[/tex]
