Answer:
t = 15.6 s
Step-by-step explanation:
According to the kinematic equation:
[tex] y_{f} = y_{0} + v_{0}*t - \frac{1}{2}gt^{2} [/tex] (1)
Where:
[tex]y_{f}[/tex]: is the final position = 1200 m
y₀: is the initial position = 0 m
V₀: is the initial speed = 0 m/s
g: is the gravity = 9.81 m/s²
t: is the time =?
From equation (1) we have:
[tex] -1200 m = 0 + 0*t - \frac{1}{2}*9.81 m/s^{2}*t^{2} [/tex]
[tex] t^{2} = \frac{2*(1200 m)}{9.81 m/s{2}} [/tex]
[tex]t = 15.6 s[/tex]
Therefore, it will take 15.6 seconds to the rock to hit the canyon floor.
I hope it helps you!
