What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)? y = x + 3 y = x + 7 y = 3x – 13 y = 3x + 5

Respuesta :

Answer:

y = x-1

Step-by-step explanation:

y = x + 4

This is in slope intercept form  ( y = mx+b where m is the slope and b is the y intercept).  The slope is 1

Parallel lines have the same slope

y = 1x+b

Using the given point

5 = 6*1+b

5-6 = 6+b-6

-1 =b

The equation becomes

y =1x-1

y = x-1