A gas originally at 27 °C and 1.00 atm pressure in a 3.3 L flask is cooled at constant pressure until the temperature is 11 °C. The new volume of the gas is ________ L.

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Answer:

THE NEW VOLUME OF THE GAS IS 3.124 L

Explanation:

Initial Temperature = 27°C = 27 + 273 K = 300 K

Pressure = constant

Initial Volume = 3.3 L

Final Temperature = 11 °C = 11+ 273 K = 284 K

Final volume = unknown

Using Charles' law, at constant pressure, the volume of a given gas is directly proportional to the temperature.

Mathematically,

V1 / T1 = V2 / T2

Re-arranging the formula by making V2 the subject of the formula

V2 = V1 T2 / T1

V2 = 3.3 * 284 / 300

V2 = 3.124 L

The new volume of the gas is therefore 3.124 L at 11°C

The new volume is 3.1 L

The parameters given in the question are

T1= 27°c

convert to kelvin

= 273 + 27

= 300k

T2= 11°c

convert to kelvin

= 273+11

= 284k

Volume 1= 3.3 L

V1/T1= V2/T2

3.3/300= V2/284

Cross multiply

284×3.3= 300×V2

937.2= 300V2

V2= 937.2/300

= 3.1

Hence the new volume is 3.1 L

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