Answer:
Option 5:
The 60W bulb has a greater resistance and a lower current than the 100 W bulb.
Explanation:
We have to compare the resistance and current of both bulbs.
Bulb A
Power = 60 W
Voltage = 110 V
Power is given as:
[tex]P = V^2 /R[/tex]
where V= voltage and R = resistance
[tex]=> 60 = 110^2 / R\\\\R = 201.6 \Omega[/tex]
Power is also given as:
P = IV
where I = current
=> 60 = I * 110
I = 60/110 = 0.54 A
Bulb B
Power = 100 W
Voltage = 110 V
To get resistance:
[tex]100 = 110^2 / R\\\\R = 121 \Omega[/tex]
To get current:
100 = I * 110
I = 100 / 110
I = 0.91 A
Therefore, by comparison, the 60W bulb has a greater resistance and a lower current.
