Answer:
v = 4.67 m
Explanation:
It is given that,
Height of the object is 24.8 cm
Height of the formed image is -3.09 cm
Object distance is 37.5 cm, it is negative always
We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :
[tex]\dfrac{h'}{h}=\dfrac{v}{u}\\\\v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ m[/tex]
So, the image is formed at a distance of 4.67 m.