Ok so there is two "puzzles" that I am being asked to solve, here are the directions: Puzzle 1: Use the digits -9 to 9 (only once) to create a real solution between 30 and 80. Show your work to justify your answer. And then the second attached image labeled image 1 - complex puzzles. Puzzle 2: Use the digits -9 to 9 to complete the puzzle below. Try all the combinations. But as you begin doing that, you will realize that in some cases you are looking for factor combinations with a particular sum or difference. You will see that some numbers have to be greater than a particular value in order to produce the product you are looking for. Show your work to confirm your solution. And then the first attached image labeled image 2 - complex puzzles. And finally a reflection: With regard to the two puzzles, please comment about the process of multiplying complex numbers. With regard to: i^n did you observe it while solving the two puzzles, and if yes, how did you compute its value? Thanks in advance for any answers.

Ok so there is two puzzles that I am being asked to solve here are the directions Puzzle 1 Use the digits 9 to 9 only once to create a real solution between 30 class=
Ok so there is two puzzles that I am being asked to solve here are the directions Puzzle 1 Use the digits 9 to 9 only once to create a real solution between 30 class=

Respuesta :

Step-by-step explanation:

Puzzle 1

(a + bi) (c + di)

ac + adi + bci + bdi²

(ac − bd) + (ad + bc)i

Matching coefficients:

30 < ac − bd < 80

ad + bc = 0

We need to pick four integers between -9 and 9 such that these two equations are satisfied.  One possible combination is:

a = 8, b = -4, c = 6, d = 3

The number would be:

ac − bd = (8)(6) − (-4)(3) = 60

Puzzle 2

Using the result from Puzzle 1:

ac − bd = 34

ad + bc = 8

Like before, it makes sense to assume b is negative.  With some trial and error, one possible answer is:

a = 5, b = -6, c = 2, d = 4