130I decays by emission of beta particles to form stable 130Xe. A 3.00 g iodine sample containing some I-130 was recorded as having 9487 disintegrations per min. k = 0.00094 min -
1. How many radioactive I-130 atoms are present in the sample?

Respuesta :

The number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.

Emission of Beta Particles takes place when there is a numerous amount of neutron to the proton in the nucleus. As a result, the neutron is transformed to proton (which is retained in the nucleus) and electron which leaves the nucleus under high energy.

Given that:

[tex]\mathbf{^{130} I \ \ \ \to ^{- \beta } \ \ \ ^{130}Xe }[/tex]

The rate of disintegration of the radioactive sample per minute is expressed by using the formula:

A = kN

where;

  • A = number of decay per unit
  • k = decay constant
  • N = total number of atomic particles present in the sample

[tex]\mathbf{N = \dfrac{A}{k}}[/tex]

[tex]\mathbf{N = \dfrac{9487}{0.00094}}[/tex]

N = 10092553.19 atoms

N = 1.01 × 10⁷ atoms  

Therefore, we can conclude that the number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.

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