Respuesta :
The number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.
Emission of Beta Particles takes place when there is a numerous amount of neutron to the proton in the nucleus. As a result, the neutron is transformed to proton (which is retained in the nucleus) and electron which leaves the nucleus under high energy.
Given that:
[tex]\mathbf{^{130} I \ \ \ \to ^{- \beta } \ \ \ ^{130}Xe }[/tex]
The rate of disintegration of the radioactive sample per minute is expressed by using the formula:
A = kN
where;
- A = number of decay per unit
- k = decay constant
- N = total number of atomic particles present in the sample
∴
[tex]\mathbf{N = \dfrac{A}{k}}[/tex]
[tex]\mathbf{N = \dfrac{9487}{0.00094}}[/tex]
N = 10092553.19 atoms
N = 1.01 × 10⁷ atoms
Therefore, we can conclude that the number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.
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