Answer:
Explanation:
a )
for convex mirror, focal length
f = + 20 / 2 = 10 cm
object distance u = 12 cm ( negative )
Using mirror formula
[tex]\frac{1}{v} + \frac{1}{u} = \frac{1}{f}[/tex]
Putting the values
[tex]\frac{1}{v} - \frac{1}{12} = \frac{1}{10}[/tex]
[tex]\frac{1}{v} =\frac{1}{10} + \frac{1}{12}[/tex]
[tex]v=\frac{12\times 10}{12+10}[/tex]
v = 5.45 cm
Size of image
=[tex]\frac{v}{u} \times size of object[/tex]
[tex]=\frac{5.45}{12} \times 9[/tex]
= 4.08 mm .
It will be erect because only erect image is formed in convex mirror .
It will be virtual .
b )
Draw ray from tip of object parallel to principal axis and after reflection appears to be coming from focus . Second ray falls on the pole and reflects back making equal angle with principal axis . Draw the reflected ray backwards to cut the other ray . They cut each other where image is formed .
