Respuesta :

gkosworldreign

Answer:

0.957mm

Explanation:

The on-axis magnetic field of a current loop(B_loop) is is 4.9 nT

B_loop = (2μAI) / (4πz^3).

Where z is defied as distance from the current carrying loop,

A is the total enclosed area of the loop,

I is the current,

μ is the permeability constant (4π*10^-7).

4.9 nT = (2* 4π*10^-7 *A *32A) / (4π* (50cm)^3)

4.9 *10^-9 = 5.12*10^-5 A

A = 0.0000957 m

=0.957mm

Parrain

Based on the current and the magnetic field strength, the edge length of the square must be 0.0098 meters or 0.98 m.

The formula for the edge length is:

= √(2 x π x length of loop³ x magnetic field strength x 10⁻⁹ T) / ( 4 x π x 10⁻⁷ H/m x current)

To use this formula, the length of the loop needs to be converted to meters:

= 50cm / 100

= 0.5 m

Edge length is:

= √(2 x π x 0.5³ x 4.9 x 10⁻⁹ T) / ( 4 x π x 10⁻⁷ H/m x 32)

= 0.0098 meters

= 0.98 cm

In conclusion, the edge length of the square is 0.0098 meters or 0.98 cm.

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