Answer:
The answer to your question is given below
Explanation:
In this reaction, the calcium metal, Ca loses two electrons to form calcium ion, Ca^2+ and two fluorine atoms, F receives the two electrons to form two fluoride ion, F^-.
This is illustrated by the following equation:
Ca —> Ca^2+ + 2e
2F + 2e –> 2F^-
Ca + 2F + 2e —> Ca^2+ + 2F^- + 2e
Cancel out 2e
Ca + 2F —> Ca^2+ 2F^-
Thus, the electronic configuration can be written as follow:
Before combination:
Calcium, Ca (20) => 2, 8, 8, 2
Two fluorine atom, F (9) => 2, 7 and 2, 7
After combination:
Calcium ion, Ca^2+ => 2, 8, 8
Two fluoride ion, F^- => 2,8 and 2,8
