Answer:
(i) t = 5s
(ii) x = 3.75*10^5 m
Explanation:
(i) To calculate the time that the electron takes to reach twice the value of its initial velocity, you use the following formula:
[tex]v=v_o+at[/tex] (1)
vo: initial velocity of the electron = 5*10^4 m/s
v: final velocity of the electron = 2vo = 1*10^5 m/s
a: acceleration of the electron = 1*10^4 m/s^2
You solve the equation (1) for t, and replace the values of the parameters:
[tex]t=\frac{v-v_o}{a}=\frac{1*10^5m/s-5*10^4m/s}{1*10^4m/s^2}=5s[/tex]
The electron takes 5s to reach twice its initial velocity.
(ii) The distance traveled by the electron in such a time is:
[tex]x=v_ot+\frac{1}{2}at^2[/tex] (2)
you replace the values of the parameters in the equation (2):
[tex]x=(5*10^4m/s)(5s)+\frac{1}{2}(1*10^4m/s^2)(5s)^2\\\\x=3.75*10^5m[/tex]
The distance traveled by the electron is 3.75*10^3m/s
