Answer:
51.33
Step-by-step explanation:
to get that, we must subtract area of segment DQE (its look like a slice of pizza) by the triangle DQE
so first, we find the area of segment DQE
Area of DQE = (58/360) * Area of whole circle
A.DQE = 58/360 * πr²
A.DQE = (58 * 3.14 * 25²)/360 = 316.34
save it then we do the second step to find the area of triangle DQE. Triangle DQE is isosceles triangle with ∠DQE = 58,
area of triangle = ½ * base * height * sin ∅
∆DEQ = ½ * DQ * EQ * sin 58°
∆DEQ = ½ * 25 * 25 * 0.848
So Area of ∆DEQ = 265.02
then finally we can find the area of segment the problem said
A.DQE - ∆DEQ = 316.34 - 265.02= 51.32 (near 51.33)
