Answer:
(12, 2) is the original point on the graph of [tex]y=f(x)[/tex].
Step-by-step explanation:
Given:
[tex]y= 5f(2(x+3))-4[/tex] has a point (3, 6) on its graph.
To find:
Original point on graph [tex]y=f(x)[/tex] = ?.
Solution:
We are given that The point (3, 6) is on the graph of [tex]y= 5f(2(x+3))-4[/tex]
If we put x = 3 and y = 6 in [tex]y= 5f(2(x+3))-4[/tex], it will satisfy the equation.
Let us the put the values and observe:
[tex]6= 5f(2(3+3))-4\\\Rightarrow 6= 5f(2(6))-4\\\Rightarrow 6= 5f(12)-4\\\Rightarrow 6+4=5f(12)\\\Rightarrow 5f(12)= 6+4\\\Rightarrow 5f(12)= 10\\\Rightarrow f(12)= \dfrac{10}{5}\\\Rightarrow f(12)= 2\\OR\\\Rightarrow 2=f(12)[/tex]
Now, let us compare the above with the following:
[tex]y=f(x)[/tex]
we get y = 2 and x = 12
So, the original point on graph of [tex]y=f(x)[/tex] is (12, 2).
