Using the formula W = mg, how many milliliters of water with a density of 1g/mL are required to weigh 0.75 newtons and g = 9.81 m/s2? Round to the nearest tenth. (Note: The mass will be in kg in your answer, thus convert to g and then to mL.) Answer: mL

Respuesta :

Given that,

Weight = 0.75 N

Acceleration due to gravity = 9.81 m/s²

Density of water = 1 g/ml

We need to calculate the volume of water

Using formula of weight

[tex]W=mg[/tex]

[tex]W=\rho Vg[/tex]

[tex]mg=\rho\times V\times g[/tex]

Where, V = volume

g = acceleration

m = mass

Put the value into the formula

[tex]0.076\times 9.8\times10^3=1\times V\times9.8[/tex]

[tex]V= \dfrac{0.076\times 9.8\times10^3}{1\times9.8}[/tex]

[tex]V=76\ ml[/tex]

Hence, The volume of water is 76 mL.

Answer:

76.5mL

Explanation:

w = mg

0.75N = m * 9.81

m = 0.75 / 9.81 = 0.0765 kg

The mass in grams is 0.0765 * 1000 = 76.5g

At a density of 1 g/mL,

76.5g ÷ 1g/ml = 76.5mL