Answer: [tex]\bold{G(t)=356e^{-0.59413t}}[/tex]
Step-by-step explanation:
Use the decay formula: [tex]P=P_oe^{kt}[/tex] where
Given: P = 44.5, P₀ = 356, k = unknown, t = 210 minutes (3.5 hours)
[tex]44.5=356e^{k(3.5)}\\\\\\\dfrac{44.5}{356}=e^{3.5k}\\\\\\0.125=e^{3.5k}\\\\\\ln(0.125)=3.5k\\\\\\\dfrac{ln(0.125)}{3.5}=k\\\\\\-0.59413=k[/tex]
Input P₀ = 356 and k = -0.59413 into the decay formula
[tex]\large\boxed{P=356e^{-0.59413t}}[/tex]