Respuesta :
Answer: The concentration of [tex]CaSO_4[/tex] in a saturated solution is [tex]3.0\times 10^{-3}M[/tex]
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]
The equation for the ionization of [tex]CaSO_4[/tex] is given as:
[tex]K_{sp}[/tex] of [tex]CaSO_4[/tex] = [tex]9.0\times 10^{-6}[/tex]
By stoichiometry of the reaction:
1 mole of [tex]CaSO_4[/tex] gives 1 mole of [tex]Ca^{2+}[/tex] and 1 mole of [tex]SO_4^{2-}[/tex]
When the solubility of [tex]CaSO_4[/tex] is S moles/liter, then the solubility of [tex]Ca^{2+}[/tex] will be S moles\liter and solubility of [tex]SO_4^{2-}[/tex] will be S moles/liter.
[tex]K_{sp}=[Ca^{2+}][SO_4^{2-}][/tex]
[tex]9.0\times 10^{-6}=[s][s][/tex]
[tex]9.0\times 10^{-6}=s^2[/tex]
[tex]s=3.0\times 10^{-3}M[/tex]
Thus concentration of [tex]CaSO_4[/tex] in a saturated solution is [tex]3.0\times 10^{-3}M[/tex]
