Respuesta :

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

[tex]333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \: - x = 630 - 801 \\ or \: - x = - 171 \\ x = 171[/tex]

ii.n(only I)= n(I) - n(I intersection T)

= 333 - 171

= 162

iii. n ( only T)= n( T) - n( I intersection T)

= 468 - 171

= 297

Venn- diagram is shown in the attached picture.

Hope this helps...

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