Answer: B) sin θ = 5/13 and D) tan θ = 5/12
Step-by-step explanation:
[tex]\csc\theta=\dfrac{r}{y}=\dfrac{13}{5}[/tex]
Use Pythagorean Theorem: x² + y² = r² to calculate x = 12
[tex]\sin \theta=\dfrac{y}{r}=\dfrac{5}{13}\qquad \qquad \qquad \csc \theta=\dfrac{r}{y}=\dfrac{13}{5}\\\\\\\\\cos \theta=\dfrac{x}{r}=\dfrac{12}{13}\qquad \qquad \qquad \sec \theta=\dfrac{r}{x}=\dfrac{13}{12}\\\\\\\\\tan \theta=\dfrac{y}{x}=\dfrac{5}{12}\qquad \qquad \qquad \cot \theta=\dfrac{x}{y}=\dfrac{12}{5}[/tex]
