Answer:
A (0,-3) and D(4,5)
Step-by-step explanation:
Given system of equations
y = x2 - 2x-3
y = 2x - 3
Solution to these will be value of x for which value of y in both equation will same.
In graph, solution will point at which curve of both equation intersect each other
To solve this we will equate the two equations
[tex]x^2 - 2x-3 = 2x-3\\ =>x^2 - 2x-3 -2x + 3 = 0\\=> x^2 - 2x - 2x -3 + 3 = 0\\\=> x^2 - 4x = 0\\=>x(x-4) = 0\\Thus\\x = 0 \ or \ x-4 = 0\\x = 0 \ or \ x = 4[/tex]
Thus, value of x is 0 and 4
we will put this value in given set of equation.
y = 2x- 3
taking x = 0
y = 2*0 -3 = 0-3 = -3
one solution is (0,-3)
taking x = 4
y = 2*4 - 3 = 8-3 = 5
Another solution is (4,5).
Though , the problem is solved we will see it this value satisfies other equation or not better understanding
y = x^2 - 2x-3
taking x = 0
y = 0^2 - 2*0-3 = -3
one solution (0,-3)
taking x = 4
y = 4^2 - 2*4-3 = 16-8 -3 = 8-3 = 5
other solution (4,5)
thus, we see both equation gives same set of solution.
