The equation to a line parallel to the line on the graph that passes through (4,15) is y = 3x + 3
The equation of a line can be represented as follows;
y = mx + b
where
Therefore,
parallel line have the same slope
(5, 35)(10, 50)
m = 50 - 35 / 10 - 5 = 15 / 5 = 3
Hence,
(4, 15)
y = 3x + b
15 = 3(4) + b
15 - 12 = b
b = 3
Therefore, the equation to a line parallel to the line on the graph that passes through (4,15) is y = 3x + 3
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