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Please Help!! And Fast!! Will give Brainliest to the Best Answers (75 points) --- The historical society hired an artist to restore a stained glass window panel. After studying the original drawings, the artist knows that panel ABCD is square. He also knows that FG is a perpendicular bisector of BC and BC ≅ BE. However, in order to restore the panel to match its original specifications, he needs to know the measure of ∠BED. Given: ABCD is a square FG ⊥ BC BC ≅ BE Step 1: Draw EC on the diagram. Use the given information to explain how you know △EGC ≅ △EGB. Add the appropriate notation to the diagram. (5 points) Step 2: Building on the information from Step 1, use the spaces below to prove that m∠BEC = 60°. Add the appropriate notation to the diagram. (5 points; 4 points for the proof, 1 point for the diagram) Statements Reasons 1. △EGC ≅ △EGB 1. Given 2. EB ≅ EC 3. Given 4. EB ≅ EC ≅ BC 5. m∠BEC = 60° Step 3: Next, use the spaces below to prove the measure of ∠ECD = 30°. Add the appropriate notation to the diagram. (5 points; 4 points for the proof, 1 point for the diagram) Given: ABCD is a square FG ⊥ BC BC ≅ BE △ECG ≅ △EBG △BEC is equilateral m∠BEC = 60° Prove: m∠ECD = 30° Statements Reasons 1. △BEC is equilateral 2. m∠GCE = 60° 3. ABCD is a square 4. Substitution Step 4: Find m∠BED. Show your work and explain your reasoning. Add the appropriate notation to the diagram. (6 points; 4 points for showing work and explaining reasoning; 1 point for final answer; 1 point for diagram) Given: ABCD is a square FG ⊥ BC BC ≅ BE △ECG ≅ △EBG △BEC is equilateral m∠BEC = 60° △ECD is isosceles Find: m∠BED

Please Help And Fast Will give Brainliest to the Best Answers 75 points The historical society hired an artist to restore a stained glass window panel After st class=

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Answer:

  1. see the first attachment for the diagram
  2. see the second attachment
  3. see the third attachment
  4. m∠BED = 135°

Step-by-step explanation:

1. We have added marks to the diagram indicating that FG is a perpendicular bisector of BC. These hash marks and angle indicator are shown in the first attachment.

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2. The proof that ∆BCE is equilateral, so all its angles are 60°, is shown in the second attachment.

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3. The proof that m∠ECD = 30° is shown in the second attachment.

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4. We know △ECD is isosceles because CE ≅ CD. Since the angle at C is 30°, the base angles at D and E are (180° -30°)/2 = 75°.

The angle of interest, ∠BED, is the sum of angles DEC (75°) and CDB (60°). Hence, ...

  m∠BED = 75° +60° = 135°

  m∠BED = 135°

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Ver imagen sqdancefan