Answer:
Step-by-step explanation:
The equation of a parabola in its vertex form is expressed as y = a(x-h)²+k where (h, k) is the vertex.
Given the equation of a parabola as y-2=1/12(x+10)
, we are to write the equation in its vertex form first as shown;
y-2=1/12(x+10)
Adding 2 to both sides of the equation
y=1/12(x+10)
+2
y = 1/12x+10/12+2
y = x/12+5/6+2
y = x/12+17/2
comparing the equation above with the quadratic equation y = ax²+bx+c
a = 0, b = 1/12, c = 17/2
The x coordinate of the vertex x = - b/2a
x = - 1/12/2(0)
x = - 1/12(0)
x =- 1/0
x = - [tex]\infty[/tex]
Substitutind x = [tex]\infty[/tex] into the y function, y =- [tex]\infty[/tex]/12+17/2
y = - [tex]\infty[/tex]
The coordinate of the vertex is ([tex]-\infty, -\infty[/tex])
