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A baseball player running forward at 3 meters per second throws a ball with a velocity of 20 meters per second at an angle of 20o with the horizontal. What is the resultant speed and direction of the throw? (Show work)

Respuesta :

Answer:

  22.8 m/s at 17.4°

Step-by-step explanation:

You want to find the resultant of ...

  3 cis 0° +20 cis 20° = (3, 0) +(18.794, 6.840) = (21.794, 6.840)

The magnitude is the root of the sum of the squares of the velocities in the horizontal and vertical directions:

  s = √(21.794² +6.840²) ≈ 22.8

The direction is found from the fact that the tangent of the angle is the ratio of vertical to horizontal coordinates:

  angle = arctan(6.840/21.794) ≈ 17.4°

The resultant velocity is 22.8∠17.4° meters per second.