What is the value of x in the figure below? In this diagram, triangle ABD- triangle CAD .

Answer:
D
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{AD}{CD}[/tex] = [tex]\frac{BD}{AD}[/tex] , substitute values
[tex]\frac{x}{13}[/tex] = [tex]\frac{3}{x}[/tex] ( cross- multiply )
x² = 39 ( take the square root of both sides )
x = [tex]\sqrt{39}[/tex] → D
The value of x in the figure showing triangles ABD & triangle CAD is;
x = √39
Now, corresponding sides of 2 congruent triangles usually have same ratio.
BD/AD = AD/DC
Thus; 3/x = x/13
cross multiply to get;
x² = 13 × 3
x² = 39
take square roots of both sides to get;
x = √39
Read more at; https://brainly.com/question/3304327