Answer:
[tex] \frac{1}{7} [/tex]
Solution,
[tex] {7}^{ - 1} \\ = \frac{1}{ {7}^{1} } \\ = \frac{1}{7} [/tex]
Laws of indices:
[tex] {x}^{0} = 1[/tex]
[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
( powers are added in multiplication of same base)
[tex] {( {x}^{m} )}^{n} = {x}^{m \times n} [/tex]
[tex] {x}^{ - m} = \frac{1}{ {x}^{m} } [/tex]
[tex] {x}^{ \frac{p}{q} } = \sqrt[q]{ {x}^{p} } [/tex]
-
- [tex]( \frac{x}{y} ) ^{n} = \frac{ {x}^{n} }{ {y}^{n} } [/tex]
-
- [tex] {(xy)}^{m} = {x}^{m} {y}^{m} [/tex]
- [tex] \sqrt[n]{x} = x \frac{1}{n} [/tex]
Hope this helps ....
Good luck on your assignment...
