Answer:
x = 3 ± [tex]\sqrt{13}[/tex]
Step-by-step explanation:
Given
y = x² - 6x - 4
To find the zeros let y = 0, that is
x² - 6x - 4 = 0 ( add 4 to both sides )
x² - 6x = 4
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = 4 + 9 , that is
(x - 3)² = 13 ( take the square root of both sides )
x - 3 = ± [tex]\sqrt{13}[/tex] ( add 3 to both sides )
x = 3 ± [tex]\sqrt{13}[/tex] ← exact solutions
