Respuesta :
Answer:
(D) [tex]f^{-1}{(x$) has an x-intercept of (-36, 0).[/tex]
(E)[tex]f^{-1}{(x)[/tex] has a range of all real numbers.
Step-by-step explanation:
Given the function: [tex]f(x)= -\dfrac23x-24[/tex]
[tex]f(x)+24= -\dfrac23x\\$Multiply both sides by $ -\dfrac32\\x=-\dfrac32(f(x)+24)\\f^{-1}(x)=-\dfrac32f(x)-36[/tex]
When y=f(x)=0
[tex]f^{-1}(x)=-\dfrac32(0)-36\\f^{-1}(x)=-36[/tex]
Therefore, [tex]f^{-1}(x)$ has a x-intercept of -36[/tex]
Also, [tex]f^{-1}(x)[/tex] has a range of all real numbers.
Therefore, Options D and E are correct.
